Chemistry, asked by tarkeshwarrai9388, 1 year ago

One mole of magnesium in the vapour state absorbs 1200 kj mol-1 energy. If the first and second ionisation energies of mg are 750 kj mol-1 and 1450 kj mol-1, respectively, then the final composition of the mixture is

Answers

Answered by chandrakishore67
0

Answer:

One mole of magnesium in the vapour state absorbed 1200 kJ mol−1 energy . If the first and second ionisation energies of Mg are 750  kJ mol−1  and 1450 kJ mol−1 respectively, the final composition of the mixture is :

Similar questions