Question

One mole of N2O4 gas was introduced into a vessel
and allowed to dissoclate in accordance with the
reaction
N2O4(g) = 2NO2(g)
The mixture resulting from the dissociation (N₂O4 & No2)
occupied 36.0 L at a total pressure of 1 atm and 45°C
a) what is the total no. of moles of gas present
b) How many moles of N₂O4 do not dissociate
c) How many moles of NO2 are produced by dissociation,
d) what are the mole fractions of N2O4 and No2 in mixture.

Please answer!!!​

Answer 1

Answer:

One mole of N2O4 gas was introduced into a vessel

and allowed to dissoclate in accordance with the

reaction

N2O4(g) = 2NO2(g)

The mixture resulting from the dissociation (N₂O4 & No2)

occupied 36.0 L at a total pressure of 1 atm and 45°C

a) what is the total no. of moles of gas present

b) How many moles of N₂O4 do not dissociate

c) How many moles of NO2 are produced by dissociation,

d) what are the mole fractions of N2O4 and No2 in mixture.