Chemistry, asked by nisha6791, 4 months ago

one mole of naphtahlene was burnt in oxygen gas at constant volume to give carbon dioxide gas and liquid water at 25°C . The heat evolved was found to be 5139.0kJ . Calculate the heat of reaction at constant pressure.( R =8.314 kJ mol *-1)

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Answered by AkshitaFeb

One mole of naphthalene (C10H8) was burnt in oxygen gas at constant volume to give carbon dioxide gas and liquid water at 25°C. ... (R = 8.314 JK-1 mol-1)

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one mole of naphtahlene was burnt in oxygen gas at constant volume to give carbon dioxide gas and liquid water at 25°C . The heat evolved was found to be 5139.0kJ . Calculate the heat of reaction at constant pressure.( R =8.314 kJ mol *-1)​

Answers

one mole of naphtahlene was burnt in oxygen gas at constant volume to give carbon dioxide gas and liquid water at 25°C . The heat evolved was found to be 5139.0kJ . Calculate the heat of reaction at constant pressure.( R =8.314 kJ mol *-1)