one mole of nitrogen and two mole of hydrogen are allowed to react in a 1 decimeter cube vessel at equilibrium 0.8 mole of NH3 is formed the concentration of hydrogen In The vessel is
Answers
Answer:
The total number of moles of gas are, 3 moles
Explanation :
The balanced equilibrium reaction is,
N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)N
2
(g)+3H
2
(g)⇌2NH
3
(g)
initially moles 1 3 0
At eqm. (1 - x) (3 - 3x) 2x
Total number of moles of gas = (1-x)+(3-3x)+2x=4-2x(1−x)+(3−3x)+2x=4−2x
As 50% of H_2H
2
is converted into ammonia. So,
\begin{lgathered}3-3x=3\times \frac{50}{100}\\\\3-3x=1.5\\\\x=0.5\end{lgathered}
3−3x=3×
100
50
3−3x=1.5
x=0.5
Now we have to calculate the total number of moles of gas.
Total number of moles of gas = 4-2x=4-2(0.5)=34−2x=4−2(0.5)=3
Therefore, the total number of moles of gas are, 3 moles
Explanation:
please mark it as a brainalist answer