Question

One mole of o2 gas having a volume equal to 22.4 litres at 0 c and 1 atm pressure is compressed isothermally so that its volume reduces to 11.2 litres. what is the work done in this process

Answer 1

may it will be helpful to you

Answer 2

Answer:

W= -7.76 atm.Lt

Explanation:

Given that

V₁= 22.4 lt

P₁= 1 atm

V₂=11.2 lt

Given that compression is isothermal.

 For isothermal process

 P₁V₁=P₂V₂

The work done in isothermal process

$W=P_1V_2\ln \dfrac{V_2}{V_1}$

Now by putting the values

$W=P_1V_2\ln \dfrac{V_2}{V_1}$

$W=1 \times 11.2\ln \dfrac{11.2}{22.4}$

W= -7.76 atm.Lt