One mole of oxygen gas at STP is equal to * 12.044× 10²³ molecules of oxygen 6.022× 10²³ atoms of oxygen 16g of oxygen 32g of oxygen
Answers
Answered by
1
One mole of Oxygen gas at STP is equal to 32 g of Oxygen
Thus, option (3) is correct.
Explanation:
- The molecular weight of Oxygen gas (O₂) = 32
- In one mole of Oxygen gas
- The number of molecules will be = 6.023 × 10²³
- The number of atoms will be = 2 × 6.023 × 10²³ = 12.044 × 10²³
- The weight of one mole of Oxygen gas will be = 32 gram
Therefore, from the given options we find that option (3) is correct
Hence,
One mole of Oxygen gas at STP is equal to 32 g of Oxygen
Hope this answer is helpful.
Know More:
Similar Question:
https://brainly.in/question/5327304
https://brainly.in/question/115862
Answered by
0
Given :
One mole of oxygen gas .
To find :
At STP , one mole of oxygen gas is equal to what .
Solution :
1 mole of oxygen gas = N number of molecules of oxygen
= 6.022× 10²³ molecules of oxygen
Molecular weight of oxygen gas = 2 * 16 = 32
1 mole of oxygen gas = 32 g of oxygen
At STP , one mole of oxygen gas is equal to 32 gram of oxygen .
Similar questions
Math,
4 months ago
CBSE BOARD X,
8 months ago
Biology,
8 months ago
Biology,
11 months ago
Physics,
11 months ago