Chemistry, asked by hafsairfanalam, 8 months ago

One mole of oxygen gas at STP is equal to * 12.044× 10²³ molecules of oxygen 6.022× 10²³ atoms of oxygen 16g of oxygen 32g of oxygen

Answers

Answered by sonuvuce
1

One mole of Oxygen gas at STP is equal to 32 g of Oxygen

Thus, option (3) is correct.

Explanation:

  • The molecular weight of Oxygen gas (O₂) = 32
  • In one mole of Oxygen gas
  • The number of molecules will be = 6.023 × 10²³
  • The number of atoms will be = 2 × 6.023 × 10²³ = 12.044 × 10²³
  • The weight of one mole of Oxygen gas will be  = 32 gram

Therefore, from the given options we find that option (3) is correct

Hence,

One mole of Oxygen gas at STP is equal to 32 g of Oxygen

Hope this answer is helpful.

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Answered by Anonymous
0

Given :

One mole of oxygen gas .

To find :

At STP , one mole of oxygen gas is equal to what .

Solution :

1 mole of oxygen gas = N_a number of molecules of oxygen

                                    = 6.022× 10²³ molecules of oxygen

Molecular weight of oxygen gas = 2 * 16 = 32

1 mole of oxygen gas = 32 g of oxygen

At STP , one mole of oxygen gas is equal to 32 gram of oxygen .

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