Question

One mole of oxygen gas at STP is equal to _______. (i) 6.022 Ã 10^23 molecules of oxygen (ii) 6.022 Ã 10^23 atoms of oxygen (iii) 16 g of oxygen (iv) 32 g of oxygen

Answer 1

One mole of oxygen gas at STP is equal to $6.022\times 10^{23}$ molecules and 32 g of mass.

Explanation:

We are given:

Moles of oxygen gas = 1 mole

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules

So, 1 mole of oxygen gas will contain $(1\times 6.022\times 10^{23}=6.022\times 10^{23})$ number of molecules

Molar mass is defined as the mass of 1 mole of a compound at STP. It is expressed in g/mol

Mass of 1 mole of oxygen gas = 32 g

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Answer 2

One mole of oxygen gas at STP is equal to  $6.023$×$10^{23}$ molecules and 32 g of oxygen.

Explanation:

Moles of oxygen gas = 1 mole

According to mole concept:

1 mole of a compound contains  $6.023$×$10^{23}$number of molecules

So, 1 mole of oxygen gas will contain $1$×  $6.023$×$10^{23}$  =  $6.023$×$10^{23}$

number of molecules.

Molar mass is defined as the mass of 1 mole of a compound at STP. It is expressed in g/mol

Mass of 1 mole of oxygen gas = 32 g

The number of molecules present in mole of oxygen gas is  equal to  $6.023$×$10^{23}$  molecules

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