Question

One mole of oxygen is allowed to expand isothermally and reversibly from 5 m^3 to 10 m^3 at 300 K. Calculate the work done in expansion of the gas

Answer 1

w = -nRT ln (Vf/ Vi)
w = -(1 mol)(8.314 J K-1 mol-1) (300 K) ln (10 m3 / 5 m3)
   = -1728 J
 

Answer 2

"Given: One mole of oxygen is allowed to expand isothermally and reversibly from 5 m^3 to 10 m^3 at 300 K.

To calculate the work done in expansion of the gas,

We will follwing formula

W = -nRT ln (Vf/ Vi)

w = -(1 mol)(8.314 J K-1 mol-1) (300 K) ln (10 m3 / 5 m3)

  = -1728 J.

Therefore answer, -1728 J.is work done in expansion of the gas"