One mole of oxygen of volume 1 litre at 4 atm
pressure to attains 1 atm pressure by result of
isothermal expansion. Find work done by the
gas.
(1) ~155 J
(2) ~206 J
(3) ~355 J
(4) ~562 J
Answers
Answered by
2
In isothermal process,
ω=2303 RTlog
10
(
P
2
P
1
)
Also, PV=nRT
⇒(
n
PV
)=RT
So, ω=(2.303)(
n
PV
)log
10
(
P
2
P
1
)
Here,
ω=(2.303)(
1
4×1
)log
10
(
1
4
)×100 J
=(2.303)(4)×(0.602)×100 J
=546 J≈562 J
Option D is correct
Answered by
3
Answer:
ANSWER
In isothermal process,
ω=2303 RTlog
10
(
P
2
P
1
)
Also, PV=nRT
⇒(
n
PV
)=RT
So, ω=(2.303)(
n
PV
)log
10
(
P
2
P
1
)
Here,
ω=(2.303)(
1
4×1
)log
10
(
1
4
)×100 J
=(2.303)(4)×(0.602)×100 J
=546 J≈562 J
Option D is correct
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