Science, asked by khatrir156, 11 months ago

One mole of oxygen of volume 1 litre at 4 atm
pressure to attains 1 atm pressure by result of
isothermal expansion. Find work done by the
gas.
(1) ~155 J
(2) ~206 J
(3) ~355 J
(4) ~562 J​

Answers

Answered by AdwaitMisra
2

In isothermal process,

ω=2303 RTlog  

10

​  

(  

P  

2

​  

 

P  

1

​  

 

​  

)

Also, PV=nRT

⇒(  

n

PV

​  

)=RT

So, ω=(2.303)(  

n

PV

​  

)log  

10

​  

(  

P  

2

​  

 

P  

1

​  

 

​  

)

Here,  

ω=(2.303)(  

1

4×1

​  

)log  

10

​  

(  

1

4

​  

)×100 J

=(2.303)(4)×(0.602)×100 J

=546 J≈562 J

Option D is correct

Answered by saxenaanu46
3

Answer:

ANSWER

In isothermal process,

ω=2303 RTlog

10

(

P

2

P

1

)

Also, PV=nRT

⇒(

n

PV

)=RT

So, ω=(2.303)(

n

PV

)log

10

(

P

2

P

1

)

Here,

ω=(2.303)(

1

4×1

)log

10

(

1

4

)×100 J

=(2.303)(4)×(0.602)×100 J

=546 J≈562 J

Option D is correct

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