Question

One mole of oxygen of volume 1 litre at 4 atm
pressure to attains 1 atm pressure by result of
isothermal expansion. Find work done by the
gas.
(1) ~155 J
(2) ~206 J
(3) ~355 J
(4) ~562 J​

Answer 1

ANSWER

In isothermal process,

ω=2303 RTlog10​(P2​P1​​)

Also, PV=nRT

⇒(nPV​)=RT

So, ω=(2.303)(nPV​)log10​(P2​P1​​)

Here, 

ω=(2.303)(14×1​)log10​(14​)×100 J

=(2.303)(4)×(0.602)×100 J

=546 J≈562 J

Option D is correct

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Answer 2

Explanation:

ANSWER

In isothermal process,

ω=2303 RTlog

10

(

P

2

P

1

)

Also, PV=nRT

⇒(

n

PV

)=RT

So, ω=(2.303)(

n

PV

)log

10

(

P

2

P

1

)

Here,

ω=(2.303)(

1

4×1

)log

10

(

1

4

)×100 J

=(2.303)(4)×(0.602)×100 J

=546 J≈562 J

Option D is correct