one mole of pcl5 is heated in a 2 litre vessel.when equilibrium is attained, the vessel is found to contain 0.2 moles of pcl5. calculate the equilibrium constant
Answers
The equilibrium reaction is PCl
5
(g)⇔PCl
3
(g)+Cl
2
(g).
The following table lists the equilibrium concentration of various species.
PCl
5
PCl
3
Cl
2
Initial
1
0
0.2
Change
-x
x
x
Equilibrium
1-x
x
0.2+x
But at equilibrium [Cl
2
]=0.2+x=0.8 or x=0.6.
Thus the equilibrium concentrations of PCl
5
,PCl
3
and Cl
2
are 0.4, 0.6 and 0.8 respectively.
The expression for the equilibrium constant is K
c
=
[PCl
5
]
[PCl
3
][Cl
2
]
=
0.4
0.6×0.2
=1.2.
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Answer:
1.2
Explanation:
The equilibrium reaction is PCl
5
(g)⇔PCl
3
(g)+Cl
2
(g).
The following table lists the equilibrium concentration of various species.
PCl
5
PCl
3
Cl
2
Initial
1
0
0.2
Change
-x
x
x
Equilibrium
1-x
x
0.2+x
But at equilibrium [Cl
2
]=0.2+x=0.8 or x=0.6.
Thus the equilibrium concentrations of PCl
5
,PCl
3
and Cl
2
are 0.4, 0.6 and 0.8 respectively.
The expression for the equilibrium constant is K
c
=
[PCl
5
]
[PCl
3
][Cl
2
] =
0.4
0.6×0.2
=1.2.
HOPE IT HELPS YOU ✓