Chemistry, asked by bidiptobose569, 1 year ago

One mole of pure ethyl alcohol was treated with one mole of pure acetic acid

Answers

Answered by wreckon1ace
0

The happening reaction is known as esterification reaction:

ACETIC ACID

CH3CH3OH + CH3COOH ETHYL ALCOHOL

= CH3COOC2H5+H2O

ETHY ETHANOATE

Ethyl Ethanoate is an ester in this case...therefore an ester will be formed

Answered by rishabhshah2609
0

Answer:

The happening reaction is known as esterification reaction:

ACETIC ACID

CH3CH3OH + CH3COOH ETHYL ALCOHOL

= CH3COOC2H5+H2O

ETHY ETHANOATE

Ethyl Ethanoate is an ester in this case...therefore an ester will be formed

Hope it helps....

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