One mole of pure ethyl alcohol was treated with one mole of pure acetic acid
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The happening reaction is known as esterification reaction:
ACETIC ACID
CH3CH3OH + CH3COOH ETHYL ALCOHOL
= CH3COOC2H5+H2O
ETHY ETHANOATE
Ethyl Ethanoate is an ester in this case...therefore an ester will be formed
Answered by
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Answer:
The happening reaction is known as esterification reaction:
ACETIC ACID
CH3CH3OH + CH3COOH ETHYL ALCOHOL
= CH3COOC2H5+H2O
ETHY ETHANOATE
Ethyl Ethanoate is an ester in this case...therefore an ester will be formed
Hope it helps....
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