Chemistry, asked by Bhakti1711, 7 months ago

One mole of van der Waals gas at 27° was isothermally expanded from 2 litres to 20 litres. Calculate Work done.

Answers

Answered by swapnilsarje17

0

Answer:

For an isothermal process

W=2.303nRTlogP2P1 whereP1=10 atm P2=1 atm

W=2.303×3×8.314×300×log110

W=17232.42 J

W=17.232.42 KJ

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