One mole of van der Waals gas at 27° was isothermally expanded from 2 litres to 20 litres. Calculate Work done.
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Answer:
For an isothermal process
W=2.303nRTlogP2P1 whereP1=10 atm P2=1 atm
W=2.303×3×8.314×300×log110
W=17232.42 J
W=17.232.42 KJ
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