One mole of zinc atom weighs 65 g Calculate the weight of one atom of zinc
sam12a13:
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1 mol of atoms = 6.022 × 10^23 atoms
Weight of one zinc atom = 65 g/mol × 1 mol/(6.022 × 10^23) = 10.8 × 10^-23 g
∴ Weight of one zinc atom is 10.8 × 10^-23 g
Weight of one zinc atom = 65 g/mol × 1 mol/(6.022 × 10^23) = 10.8 × 10^-23 g
∴ Weight of one zinc atom is 10.8 × 10^-23 g
Answers
Answered by
2
6.023*10^23 atoms weigh 65g
hence 1 atom weigh 65/6.023*10^23g
=10.7*10^-23g
=1.07*10^-22g
hence 1 atom weigh 65/6.023*10^23g
=10.7*10^-23g
=1.07*10^-22g
Answered by
0
It is 65 divided by Avogadro no.
which is 6.023 × 10²³
So, answer is 10.8÷10²³
which is 6.023 × 10²³
So, answer is 10.8÷10²³
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