one mole Photon each of the frequency is 250 per second would be approximately a Total energy of.
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Answered by
4
All the frequency 2.75 . 10 rase 14 Hz
the energy of photon in hydrogen atom is given by the formula E=hv where h is planck constant and v is the frequency. after that i got an answer different
from the correct answer which is 110 kj.
formula E=hv is for the energy is one photon. you have a mole of photons. you have to use a slightly modified
form:
E=Nhv
where N is the number of photons in this case
N=n.Na
1mol×6.02×10rase23
molrase-1
6.02×10rase23
note that you are being asked to report energy in kilojoules not kilojoules per mole
if l use E=nNahv,i get the correct answer you cite of 110kj.
the energy of photon in hydrogen atom is given by the formula E=hv where h is planck constant and v is the frequency. after that i got an answer different
from the correct answer which is 110 kj.
formula E=hv is for the energy is one photon. you have a mole of photons. you have to use a slightly modified
form:
E=Nhv
where N is the number of photons in this case
N=n.Na
1mol×6.02×10rase23
molrase-1
6.02×10rase23
note that you are being asked to report energy in kilojoules not kilojoules per mole
if l use E=nNahv,i get the correct answer you cite of 110kj.
Answered by
9
Answer:
Explanation:
The enegry of one photon is given by
E=hv
Thus, the enegry of one mole of photons is obtained by multiplying the above relation by Avogadro's constant:
Total energy =hVN0
=(6.6×10−34Js)(250s−1)(6.02×10−23mol−1)
=9933×10−11J
=0.9933×10−7J
=0.9933erg(10−7J=1erg)
≈1erg
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