one molecule of a compound contains one atom of calcium at mass 40u. Two atoms of hydrogen and 1.99 ×10^-22g of other elements. Thw molecular mass of the compound is nearly
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Answer:
161 u
Explanation:
1.99 x 10^-22g = 119u (Divide by 1.66 x 10^-24)
Given Ca = 40u
2 Hydrogen atoms = 2x1u = 2u
Total - 119 + 40 + 2 = 161 u
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