Question

One molecule of glucose on complete oxidation yields *
(a) 40 ATP
(b) 83 ATP
(c) 35 ATP
(d) 38 ATP​

Answer 1

Total yields for one glucose molecule (C6 H12 O6 )

2 NADH from glycolysis

2 NADH from pre - kreb's

6 NADH from kreb's cycle

2 FADH2 from kreb's cycle

4 total ATP from glycolysis

2 total ATP from kreb's cycle

TOTAL YIELDS FOR ONE GLUCOSE MOLECULE...

2 net ATP/ NADH = 4 total ATP

3 net ATP / NADH = 6 total ATP

3 net ATP/ NADH = 18 total ATP

2 net ATP/ FADH2 = 4 total ATP

                               = 4 net ATP / GLUCOSE

                               = 2 net ATP / GLUCOSE

  TOTAL ATP = 38 ATP

HENCE, answer is d i.e., 38 ATP

HOPE IT HELPS..

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Answer 2

$\huge\boxed{\fcolorbox{yellow}{blue}{A)83 ATP}}$