Question

One more interesting and genius type question for you
Answer :-( x^2+5x+6 , k= -9,-3,-2,3)

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:-

$Dividend = \: \\ (Divisor \: × \: Quotient \: + \: Remainder)$

=x³+2x²+kx+3

=x-3

21 is the Reminder

x³+2x²+kx+3=(x-3)+21

Quotient is this

$(\frac{(x3 + 2x \times {}^{2} + kx)}{(x - 3)}$

0 is the reminder

Remainder=0

3(k+15)-18=0

k+15=6

k=-9

Following steps:

• x³+2x²-9x+3=(x-3)(x²+5x+6)+21)
• x³+2x²-9x-18=(x-3)(x²+2x+3x+6)
• x³+2x²-9x-18=(x-3){x(x+2)+3(x+2)
• x³+2x²-9x-18=(x-3)(x+3)(x+2)

Hence,zeroes are 3 , -3 and -2

Therefore, Value of k=-9

Zeroes of cubic polynomial

( 3 , -3 and -2)

$\huge\textbf\red{Hope-It-Helps!!! }$