One motorist travels 5 km.hr faster than another. They leave from the same place and travel in opposite directions. What is the rate of each if they are 195 km apart after 3 hours?
Answers
Step-by-step explanation:
Let x be the rate of the slower motorist, in km/h.
Then the rate of the faster is (x+5) km/h, according to the condition.
In 3 hours, the slower motorist will cover the distance of 3x kilometers.
while the faster will cover 3(x+5) kilometers.
The total distance is the sum of partial distances, so your equation is
3x + 3(x+5) = 195
3x + 3x + 15 = 195
6x = 195 - 15 = 180 ====> x = 180%2F6 = 30.
Answer. The slower motorist rate is 30 km/h; that of the faster motorist is 35 km/h.
Answer:
30 km/hr and 35 km/hr
Step-by-step explanation:
let's assume the speed of one motorist as x km/hr.
As the speed of one motorist 5 km/hr faster than the other, the speed of another motorist will be (x+5) km/hr.
Both motorist starts from the same place and travels in opposite direction. stop their combined speed will be
x km/hr + (x + 5) km/hr = 2x + 5 km/hr
Now, Speed = distance/time
2x+5 km/hr = 195 km / 3 hr
2x+5 = 65
2x = 60
x = 30
So the speed of motorists are 30 km/hr and 35 km/hr.