Math, asked by rr6255428, 1 day ago

one natural number is greater than the second natural number by 5. if the sum of the squares of these numbers is 73 then find these numbers

Answers

Answered by kmaneet653
7

Answer:

let the first natural no. be x+5

let the second natural no.be x

ATQ,

x+5+x=73

2x+5=73

2x=73-5

x=68÷2

x= 34

Step-by-step explanation:

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