Question

one natural number is thrice the other natural number sum of their squares exceeds 13 times the greater number by 4 find the two nu7mbers

Answer 1

Answer:

Let two natural no be a, b;

Now one no. Is thrice of other

3a=b.......1

And sum of their squares exceeds 13 times the greater number by 4

a^2+b^2=13b+4.........2

Put 1 in 2

10a^2-39a-4=0

a=-1/10&a=4

But a is natural so a is not equal to - 1/10

Now put a=4 in 1

b=3a

b=3*4=12