Math, asked by abinash88281, 1 year ago

One needs to recognize that averages and mixtures are effectively two sides of the same coin. This question is designed to drive home that point.

Answers

Answered by QueenOfKnowledge
0

Let average in class C = x. Average of class B = x +16. Average of class A = y

y = 2 + 20y+30(x+16)+50x10020y+30(x+16)+50x100

(y - 2) * 10 = 2y + 3x + 48 + 5x

10y - 20 = 2y + 8x + 48

8y - 8x = 68

y - x = 8.5. This is the difference between average of class A and class C.

The question is "This question is designed to drive home that point."

Hence, the answer is "This is the difference between average of class A and class C.".

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