One newton into dyne using dimensional formula
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the dimensional formula of Force F = [M1 L1 T-2]
So a =1, b=1, c=-2
Now because Newton is in m.k.s system, we have
M1 = 1kg
L1 = 1m
T1 = 1s
M2 = 1g
L2 = 1cm
T2 = 1s
n1= 1 Newton
n2 = ?
Using the formula
n2= n1[M1/M2]a[L1/L2]b[T1/T2]c
n2=1 [1kg/1g]1[1m/1cm]1[1s/1s]-2
n2=1[1000g/1g]1[100cm/1cm]1x1
n2=1000×100 = 100000 = 105 dynes
Hope it helps you!!
So a =1, b=1, c=-2
Now because Newton is in m.k.s system, we have
M1 = 1kg
L1 = 1m
T1 = 1s
M2 = 1g
L2 = 1cm
T2 = 1s
n1= 1 Newton
n2 = ?
Using the formula
n2= n1[M1/M2]a[L1/L2]b[T1/T2]c
n2=1 [1kg/1g]1[1m/1cm]1[1s/1s]-2
n2=1[1000g/1g]1[100cm/1cm]1x1
n2=1000×100 = 100000 = 105 dynes
Hope it helps you!!
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