Question

One no. Exceeds the other by 9 and their sum is 49 take one no. As x

Answer 1

$\huge\underline{\red{Answer}}$

$Let \: one \: number \: be \: x.$

$The \: other \: number = x+9$

$Their \: sum = 49$

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$That \: is \: ,$

$(x ) + (x + 9) = 49$

$x + x + 9 = 49$

$2x + 9 = 49$

$2x = 49 - 9$

$2x = 40$

$x = \frac{40}{2}$

$x = 20$

$So, the \: Other \: number = x + 9 \\ = (20) + 9 \\ = 29$

The numbers are 20 & 29 .

$Hope \: \: this \: \: helps \: \: you \: !$