one number exceeds an other by 5, and their sum is 29;find them?
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Answered by
1
12 and 17
Let first number be x. and another be x + 5.
According to question
x + ( x + 5 ) = 29
2x + 5 = 29
2x = 24
x = 12
Therefore the numbers are 12 (x) and 17(x+5)
Let first number be x. and another be x + 5.
According to question
x + ( x + 5 ) = 29
2x + 5 = 29
2x = 24
x = 12
Therefore the numbers are 12 (x) and 17(x+5)
ShubhranshuSuraj:
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Answered by
1
let that one number be x
second number= x+5
therefore x+x+5=29
2x+5=29
2x=29-5
2x=24
x=24/2
x=12
2nd number is x+5
= 12+5
=17
mark as brainliest pls
second number= x+5
therefore x+x+5=29
2x+5=29
2x=29-5
2x=24
x=24/2
x=12
2nd number is x+5
= 12+5
=17
mark as brainliest pls
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