one number exceeds another number by 36.if sum of both numbers is 48.find the numbers.find the smallest number,having four different prime factors
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x + (x + 36) = 48
= 2x + 36 = 48
= 2x = 48-36
= 2x = 12
= x = 12/2
= x = 6.
So, 6+36 = 38 is your answer.
= 2x + 36 = 48
= 2x = 48-36
= 2x = 12
= x = 12/2
= x = 6.
So, 6+36 = 38 is your answer.
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