Question

one number exceeds another number by 36.The sum of number is 48 than the number are​

Answer 1

Step-by-step explanation:

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Answer 2

Given :

⬤ One Number Exceeds another Number by 36 .

⬤ Sum of the Numbers is 48 .

To Find :

⬤ The Numbers .

Solution :

Let :

• First Number be = x .
• Second Number be = x + 36 .

Now :

As given that , Sum of the Numbers is 48 . Hence ,

$\sf{x+x+36=48}$

2x + 36 = 48

2x = 48 - 36

2x = 12

x = 12/2

x = 6

Therefore , The Value of x is 12 .

Hence ,

First Number = x

= 6

Second Number = x + 36

= 6 + 36

= 42

Therefore , The two Numbers are 6 and 42 .