One number exceeds another number by 36. The sum of numbers is 48 then the
numbers are
(a) 40, 08 (b) 36, 12 (e) 42, 06 (d) 32,16
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SOLUTION:→
Given :→
- One number exceeds another number
by 36.
- The sum of numbers is 48
_____________________
To find :→
- Required number
_____________________
Let the one of the number is 'x'
then the other number will be
x + 36. And the sum of number
is 48.
_____________________
So,
⇒ x + x + 36 = 48
⇒ 2x + 36 = 48
⇒ 2x = 48 - 36
⇒ 2x = 12
⇒ x = 12 ÷ 2
∴ x = 6
_____________________
So,
One of the number is = x = 6
Other number is = x + 36 = 6 + 36 = 42
Therefore option 'e' (42, 06) is correct
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