Question

one number is 1 more than 7 times the other number. if their sum is 73 more than twice the smaller number. find the numbers​

Answer 1

Answer:

85 and 12

Step-by-step explanation:

let smaller be y and greater be x

as per que

x = 1 + 7y

y + x = 73 + 2y

replacing x

y + 1 + 7y = 73 + 2y

8y - 2y = 73 - 1

6y = 72

y = 72÷6

y= 12

x = 1 + 7× 12

x = 85

Answer 2

Answer:

Let x and y be the two numbers.

Then,

x - 1 = 7y

=> x = 7y + 1 ---------->(i)

And,

x + y -73 = 2y

=> (7y + 1) + y -73 = 2y [ substituting the value of x from equation (i)]

=> 8y - 72 = 2y [Adding up the like terms]

=> 8y - 2y = 72 [ Transposing 2y and -72]

=> 6y = 72

=> y = 72/6

=> y = 12 --------->(ii)

Now, substituting the value of y in equation (i),we get

x = 7x 12 + 1 = 84 + 1 = 85

Hence, the numbers are 85 and 12