Question

one number is 10 more than the other . if their number is 52, find the numbers.​

Answer 1

Answer:

x=21

Step-by-step explanation:

1st number= x

2nd number =x + 10

their sum= 52

numbers = x + (x+10)=52

2x+10=52

2x=52-10

2x= 42

x=42/2

x=21

Answer 2

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21 and 31

Step-by-step explanation:

Let one of the number be '$\large {x}$'

Another number = '10+$\large {x}$'

Sum of the numbers = 52

$ATQ, \: x + 10 + x = 52 \\ = > 2x + 10 = 52 \\ = > 2x = 52 - 10 \\ = > 2x = 42 \\ = > x = 42 \div 2 \\ = > x = 21$

One number = $x$ =

21

Another number = 10+$x$ = 10+(21) =

31