Question

One number is 10 more than the other. If their sum is 52, find the numbers.

Pls answer my question.
Who ever will answer it properly steps by steps.
I will mark him as a brainlist.
✌️✌️✌️✌️✌️✌️

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Answer 1

Ello..✌✌

Let first number be x

then the other number will be = x+10

Now, according to the question,

x+x+10= 52

=> 2x = 52-10

=> x = 42/2 = 21

So, the required numbers

are 21 and 31.

Answer 2

Answer:

21 and 31 are the two numbers whose sum is 52 and one number is 10 more than the other number.

Step-by-step explanation:

Let the first number be x.

Second number are 10 more than the first number.

Then, Second number be (x+10)

According to the question

Sum of two number = 52 (given)

x + (x+10) = 52

2x + 10 = 52

2x = 52-10

2x = 42

x = 42/2

x = 21

First number = x = 21

Second number = (x + 10)

Second number = 21 + 10

Second number = 31

21 and 31 are the two numbers .