One number is 10 more than the other.if their sum is 52 ,find the number
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let the first number =x
and second number= y
according to question:-
x+10= y ......eq.1
and x+y = 52 .....eq.2
put eq.1 in eq.2 , we get:-
x+x+10=52
2x= 52-10
x= 42/2
x=21
put value of x in eq. 2, we get:-
21+y= 52
y=52-21
y=31
note:- in this question I used the substitution method
you can use either the cross multiplication or elimination method to find the solution but the method is lengthy to get the same answer. lol
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