Question

one number is 21/2 times as large as another the sum of the number is28 find the number​

Answer 1

Answer:

let one no=x and another no=21/2x

Step-by-step explanation:

x+21/2x=28

2x+21x/2=28

23/2x=28

x=28 ( 2/23)

x=56/23

another no.=21/2(56/23)

=21(56)/46

=588/23

hope it helps you

Answer 2

Answer:

∴ The required numbers are $\frac{56}{23}$ and $\frac{588}{23}$.        

Step-by-step explanation:

In context with question asked,

• We have to the numbers.
• It is given that, one number is $\frac{21}{2}$ times as large as another.
• Let, $x$ be the number.
• Other number = $\frac{21x}{2}$
• Sum of two numbers = $28$
• According to given data, the equation becomes,

           $x+\frac{21x}{2}=28$

          ∴ $\frac{2x+21x}{2} =28$

               ∴ $23x=28\times 2$

               ∴ $23x=56$

                  ∴ $x=\frac{56}{23}$

• Now, the other number = $\frac{21x}{2}$ = $\frac{21\times 56}{2\times 23}$ = $\frac{1176}{46}$ = $\frac{588}{23}$
• ∴ The required numbers are $\frac{56}{23}$ and $\frac{588}{23}$.