Question

one number is 3 less than the two times of the other .if their sum is increased by 7,the reault is 37.find other numbers

Answer 1

Let the 1st number be x

Let the 2nd number be 2x

3 less than the two times of the other = 2x - 3

Sum increased by 7 = 2x - 3 + 7

According to the question,

x + 2x - 3 + 7 = 37

3x + 4 = 37

3x = 37 - 4

3x = 33

x = $\frac{33}{3}$

x = 11

1st number = x = 11

2nd number = 2x - 3 = 19

Answer 2

$\textbf {Answer -}$

Let the first number be $\textbf {x}$.

And the second number be $\textbf {2x}$.

Now, one number is 3 less than the two times of other = $\textbf {2x - 3}$

Also the sum is increased by 7. Therefore = $\textbf {2x- 3 + 7}$

Now, according to the question :

$x + 2x - 3 + 7 =37$

$3x = 37 - 4$

$3x = 33$

$\textbf {x = 11}$.

Second number = $\textbf{2x - 3 = 19}$