Question

One number is 3 less than two times the other. If their sum is increased by 7. The result is 37. Find the
number.​

Answer 1

Answer:

Let one number be = x

Then other number= 3–2x

$(x) + (3 - 2x) = 37 - 7$

$x + 3 - 2x = 30$

$3 - 3x = 30$

$3 - 3x = 30$

$3 - 30 = 3x$

$- 27 = 3x$

$3x = - 27$

$x = - 9$

Then the one number =x= –9

Then the other number =

$3 - 2x$

$= 3 - 2x \times - 9$

$= 3 - 18$

$= - 15$

Hence solved

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Answer 2

Answer:

11

Step-by-step explanation:

assume one number is x

another number will be...2x-3

their sum increased by 7 result will be37

x+2x-3+7=37

3x+4=37

3x=37-4

3x=33

x=11

the number is 11 another number is 19