One number is 3 times another number.if 15 added to both the numbers,then one of the new number becomes twice the other new number.find the number
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let one no be x and other y
x=3y
(x+15) = 2 (3y + 15)
substituting x = 3y
3y + 15 = 6y + 30
y = (-5)
x = ( -15)
x=3y
(x+15) = 2 (3y + 15)
substituting x = 3y
3y + 15 = 6y + 30
y = (-5)
x = ( -15)
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