Math, asked by asdfqwert9775, 1 year ago

One number is 3times another number. If 15 is added to both the nimbers then one of the new numbers becomes twice that of the other new number find the numbers

Answers

Answered by BrainlyPrincess
84
Let the number be x

Let the other number be 3x

If 5 added to both the numbers, 1st number = x + 15 and 2nd number = 3x + 15

One of the new numbers becomes twice that of the other new number = 2(x + 15)


According to the question,

3x\:+ \:15\:=\:2(x\:+\:15)

3x\:+\:15\:=\:2x\:+\:30

3x\:-\:2x\:=\:30\:-\:15

x\:=\:15


∴ 1st number ➾ x

\blue{\boxed{\blue{\boxed{\green{\mathbb{15}}}}}}


∴ 2nd number ➾ 3x

➾ 3 × 15

\blue{\boxed{\blue{\boxed{\green{\mathbb{45}}}}}}



Verification :

3x + 15 = 2(x + 15)

➾ 3x + 15 = 2x + 30

➾ 3x - 2x = 30 - 15

➾ x = 15

➾ 15 = 15

∴ LHS = RHS ✔✔

smartyAnushka: Nice answer sis.....☺❤❤
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BrainlyPrincess: thank you so much
BrainlyPrincess: thank you ♥
vikram991: nice answer diii
Answered by sherafgan354
43

Answer:

Required Numbers are 45 and 15

Step-by-step explanation:

Let us suppose that one number is x and other is y

According to given condition

x = 3y      .............(i)

Now 15 is added to both Numbers by which it becomes

x+15 and y +15

Then According to second condition

(x+15) = 2(y+15)              ............(ii)

Now we have got two equations and from this we can find the two numbers

From first equation we have

x = 3y

Putting this value in equation (ii) which is

(x+15) = 2(y+15)            

Putting the value of x here

(3y+15) = 2(y+15)

3y + 15 = 2y + 30

Subtracting 15 from both sides

3y + 15 -15 = 2y + 30 -15

3y = 2y + 15

Subtracting 2y from both sides

3y - 2y = 2y + 15 -2y

y = 15

Now we got the value of y for the value of y we can use equation (i)

which is

x = 3(y)

putting value of y here

x = 3(15)

x = 45


So value of y = 15 and value of x = 45

Now the two Numbers are 45 and 15


sherafgan354: thanks
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