Question

one number is 4 less than three times another number.if their sum is increased by 5 the result is 25. ​

Answer 1

Then if their sum is increased by 5, the result is 25, so we get another equation as: x+y+5 = 25. 3y-4=x can be written as 3y -x= 4 and x+y+5=25 can be written as x+y =25–5= 20.

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Answer 2

Answer:

Here, The first number is 16 and the other number is 4.

Step-by-step explanation:

Here, As per our given question,

=Let the the 1st number be x

Let the other number be y

Now,=x-3y=4 -(1st)eq.

=(x+y)+5=25

=x+y=25-5

=x+y=20 -(2nd)eq.

Now, On solving both equations by elimination method, we will multiply with 1 in eq.1 and with 3 in eq. 2,and then addboth the equations,

= x -3y=4

=3x+3y=60

After solving, we get,

=x+3x=60+4

=4x=64

=x=64/4

=x=16

Now, by putting value of x in eq. 1, we get,

=16-3y=4

=(-3y)=4-16

=(-3y)=(-12) (As here both sides are equal and have same sign)

=3y=12

=y=12/3

=y=4

So, The first number =16 and the other number =4.

Now, Proof:

=x-3y=4 (As given in question)

=16-3×4=4

=16-12=4

=4=4

LHS=RHS (Proved)

Thank you.