Question

one number is 5 less than the other.if the difference of theirs square is 45 ,find the numbers​

Answer 1

Answer:

7 and 2

Step-by-step explanation:

let the two numbers be x and y then x=y-5 and y2-x2=45

y2-(y-5)2=45=y2-(y2-10y+25)=45=y2-y2+10y-25=10y-25

=10y=45+25=7then divide both side by 10then y=7 then x=2

Answer 2

Y= x-5
Y^2- x^2 = 45
(X-5)^2 -x*2 =45
X^2 +25 -10x -x^2 =45
25-10x=45
-10x= 20
X= -2
Y= x-5
i.e. y= -2-5
= -7
Numbers are -2 and -7