Question

One number is 5 more than a second number Of 3 times the smaller number plus 4 times the larger is 104, find the two numbers​

Answer 1

Answer:

Additionalknowledge

Knowledge about Quadratic equations -

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

★ A quadratic equation have 2 roots

★ ax² + bx + c = 0 is the general form of quadratic equation

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Answer 2

Answer:

Assume that one number is = x

Then the other number is = x + 5

Here the larger number is x + 5

Four times the larger number is = 4(x+5)

Here the smaller number is = x

Three times the smaller number is = 3x

Four times the larger number plus 3 times the smaller is = 97

==> 4(x+5) + 3x = 97

==> 4x + 20 + 3x = 97

==> 4x+ 3x + 20 = 97

==> 7x + 20 = 97

subtract 20 from both sides of the equation

==> 7x + 20 - 20 = 97 -20

==> 7x = 77

Divide both sides of the equation by 7

==> 7x/7 = 77/7

==> x = 11.

So the first number is 11

Then the other number, which is 5 more than that of first = 11+ 5= 16

The second number is 16.

To check the answers....it is given that...Four times the larger number plus 3 times the smaller is 97

That is 4*16 + 3*11 = 64 + 33 = 97.

That is our answer is correct.