Question

One number is 6 less than the other. If the difference bettween of their squares is 72, find the numbers.​

Answer 1

Answer:

the numbers are 9 and 3

Step-by-step explanation:

let the numbers be x and x - 6

given x² - (x - 6)² = 72

=> x² - (x² + 36 - 12x) = 72

=> x² - x² - 36 + 12x = 72

=> 12x = 72 + 36

=> 12x = 108

=> x = 9

therefore the numbers are 9 and 3

Answer 2

Answer:

let one number be x and other be y

x-y-=6

x^2-y^2=72

(x-y)(x+y)=72

x+y=72/6

x+y=12

x-y-=6

adding these

2x=18

x=9

y=3