Question

one number is 6 less than the other if the difference of their square is 72 find the numbers
so​

Answer 1

Answer:

9,3

Step-by-step explanation:

let 1st number be x,then other will be x-6

sum of squares =72

therefore (x)^2-(x-6)^2=72

x^2-x^2-36+12x=72

12x=72+36

12x=108

x=9

1st no.=9

2nd no.=9-6

=3

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