Question

one number is 6 less than the other if the difference of their squares is 72 find the numbers​

Answer 1

Answer:

first no. be x-6

second no. be x

x^2 - (x-6)^2=72

x^2 - (x^2+36-12x) =72

open brackets

x^2 - x^2 -36 - 12x =72

-36 -12x =72

-12x = 72+36

-12x = 108

x = 108/-12

x = -9

(hint :- x^2 means x square)

Answer 2

Answer:

let the no be x

therefore the other no be x-6

x square - (x-6)square = 72

x square - (x square + 36 - 12x )= 72

12x = 72 + 36

12x = 108

x = 108/12

x = 9