Question

one number is 6 less than the other if the difference of their square is 72 find the numbers​

Answer 1

Step-by-step explanation:

x = 33

y = 39

Hope it helps:)

Answer 2

Answer:

First number  = 9

Other number = 3

Step-by-step explanation:

Let the first number = x

Then other number = x-6

According to question the difference of their square = 72

$x{2} - (x-6)^{2}=72$

$x^{2} -(x^{2}-2.x.6+36) = 72$

$x^{2}-(x^{2}-12x+36)=72$

$x^{2}-x^{2} +12x-36=72$

12x = 72 + 36

12x = 108

x = $\dfrac{108}{12}$

x = 9

First number = x

First number  = 9

Other number = x-6

                       = 9-6

Other number = 3