one number is 6 more than a second number as sum of two numbers is 16 find the numbers
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let x and y be the 2 numbers....(x>y)
BTP,
x=y+6..............[i]
x+y=16.............[ii]
∴(y+6)+y=16
or, 2y=16-6
or, 2y=10
∴y=5
now,∵x=y+6,
so, x=5+6=11
∴x=11 & y=5
☺☺☺☺☺
BTP,
x=y+6..............[i]
x+y=16.............[ii]
∴(y+6)+y=16
or, 2y=16-6
or, 2y=10
∴y=5
now,∵x=y+6,
so, x=5+6=11
∴x=11 & y=5
☺☺☺☺☺
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