Question

One number is 6 more than a second number.. Thr sum of the two number iw 16. Find the number​

Answer 1

Answer:

let the second no. be X

first no. = 6+x

A/Q

x + (6+x) = 16

=> x+6+x= 16

=> 2x+6=16

$= > 2x = 16 - 6$

$= > x = \frac{10}{2} \\ = > x = 5$

second no. = 5

first no. = 6+x

= 6+5

= 11

Answer 2

Given -

One number is 6 more than a second number. The sum of the two number is 16.

To find -

• Numbers

Solution -

Let the required number be x and y

• According to the question

One number is 6 more than a second number.

• x = y + 6

→ x - y = 6 ---(i)

The sum of the two number is 16.

• x + y = 16 ---(ii)

Add both the equations

→ (x - y) + (x + y) = 6 + 16

→ x - y + x + y = 22

→ 2x = 22

→ x = 11

Substitute the value of x in eqⁿ (ii)

→ x + y = 16

→ 11 + y = 16

→ y = 16 - 11

→ y = 5

•°• Required numbers

• x = 11
• y = 5

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