One number is 7 more than another and its square is 77 more than the square of the smaller number.what are the number?
Answers
Answered by
6
let the larger (one number) number be x
and the smaller number (another number) be y
A/Q
x=y+7..............................(i)
it's square
x²=y²+77.......................(ii)
using (i) in (ii) we get
(y+7)²=y²+77
y²+14y+49=y²+77
14y=77-49
y=28/14
y=2
putting the value of y in (i) we get
x=2+7
x=9
∴ the numbers are 2 and 9
Hope this helps you.
and the smaller number (another number) be y
A/Q
x=y+7..............................(i)
it's square
x²=y²+77.......................(ii)
using (i) in (ii) we get
(y+7)²=y²+77
y²+14y+49=y²+77
14y=77-49
y=28/14
y=2
putting the value of y in (i) we get
x=2+7
x=9
∴ the numbers are 2 and 9
Hope this helps you.
Answered by
2
Answer:let one number be x
other no =x+7
(x+7)² -77 =x²
x²+49+14x-77=x²
x²-28+14x=x²
x²-x²+14x = 28
14x= 28
x= 2
other no = x+7 =2+7 =9
the numbers are 2 and 9
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