Question

. One number is 7 more than another and its square is 77 more than the square of the smaller number.

What are the numbers?
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Answer 1

Given :-

• One no. is 7 more than another
• Its square is 77 more than the square of smaller no.

To Find :-

• Both numbers

SoluTion :-

Let one number be x

Other number = (x + 7)

According to the question,

$\sf {(x + 7)^{2} - 77 = x^{2}}\\\\\\\sf {x^{2} + 49 + 14x - 77 = x^{2}}\\\\\\\sf {x^{2} - 28 + 14x = x^{2}}\\\\\\\sf {x^{2} - x^{2} + 14x = 28}\\\\\\\sf {14x = 28}\\\\\\\sf {x = 2}$

Thus, one number = x = 2

Another number = x + 7 = 9

Answer 2

Answer:

Step-by-step explanation:

= (x+7)²=x²+77

= x²+49+14x = x²+77

= x = 28/14 = 2

= x = 2

= 7+2 = 9