one number is 7 more than another and its square is 77 more than the square of the smaller number . what are the numbers?
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one number is 7 more than another and its square is 77 more than the square of the smaller number . what are the numbers
i also have same problem
i also have same problem
abhishekkumar17:
2&9
Answered by
9
Hi ,
Let x and ( x + 7 ) are two numbers ,
( x + 7 )² = x² + 77
x² + 14x + 49 = x² + 77
14x = 77 - 49
14x = 28
x = 28/14
x = 2
I hope this helps you.
:)
Let x and ( x + 7 ) are two numbers ,
( x + 7 )² = x² + 77
x² + 14x + 49 = x² + 77
14x = 77 - 49
14x = 28
x = 28/14
x = 2
I hope this helps you.
:)
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