Question

one number is 7 more than another and its square is 77 more than the square of the smallest number what are the number

Answer 1

let one number is x,and another is x+7.
$( {x + 7)}^{2} - {x}^{2} = 77 \\ {x}^{2} + 14x + 49 - {x}^{2} = 77 \\ 14x = 77 - 49 \\ 14x = 28 \\ x = 2 \\ 1st \: number \: is \: 2. \\ another \: number \: is \: 2 + 7 = 9$

Answer 2

refer to the above pic for answer